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Algebra

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Source: — Problem Solving |
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by truplayer256 » Fri Feb 13, 2009 4:35 pm
(x+3)^(2)+6(x+3)+9=0
(x+3)[(x+3)+6]=-9
(x+3)(x+9)=-9
x^2+12x+27=-9
x^2+12x+36=0
(x+6)^(2)=0
x+6=0
x=-6
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by jhhatdaddy » Sat Feb 14, 2009 4:38 am
isnt it even easier than that?

(x^2+6x+9) + 6(x+3) + 9 = 0

x^2+6x+9+6x+18+9=0
x^2+12x+36-0
(x+6)^2=0
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by deepoe » Sat Feb 14, 2009 6:07 am
truplayer256 wrote:(x+3)^(2)+6(x+3)+9=0
(x+3)[(x+3)+6]=-9
(x+3)(x+9)=-9
x^2+12x+27=-9
x^2+12x+36=0
(x+6)^(2)=0
x+6=0
x=-6
Did you divide the (x+3) from 6(x+3) ?
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what to do next

by Etoiles » Sat Feb 14, 2009 10:12 am
2 ways
either develop as and solve
or recognize that X^2 +6X+9 is (X+3)^2
and factorize x+3 and then solve
and refactorize x+6 Recognizing that X^2 +12X+36
is (X+6 ) ^2

ps it is the formula (a+b)^2 = a^2 +b^2+2ab

hope it helps
when there is a will there is a way ... believe in yourself ... kind regards
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by deepoe » Mon Feb 16, 2009 2:24 am
Thanks but what do you do with the ^2?
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