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Jurors

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Senior | Next Rank: 100 Posts
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by acorra » Sun Nov 09, 2008 9:55 am
twelve jurors must be picked from a pool of [i]n[/i] potential jurors. If [i]m[/i] of the potential jurors are rejected by the defense counsel and the prosecuting attorney, how many different possibile juries could be picked from the remaining potential jurors?

1) if one less potential juror had been rejected, it would be possibile to create 13 different juries

2) n= m + 12


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Andrew
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Source: — Data Sufficiency |
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by lachlanc » Mon Nov 10, 2008 7:53 am
I say D

1) if one less potential juror had been rejected, it would be possibile to create 13 different juries

13 = 13!/12! Therefore we know that if 1 less juror has been rejected, there would have been 13 to choose from. 13-1 = 12
12!/12! = 1 possible jury
SUFFICIENT

2) n= m + 12

this statement tells us that all but 12 were rejected
m= n - 12 Therefore 12 were not rejected
12!/12! = 1
SUFFICIENT

What's the OA?
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by 4meonly » Tue Nov 11, 2008 8:47 am
I've got D too

(1)
12C(n-m+1)=13
(n-m+1)=13
n-m=12
12C12 = 1
Suff

(2)
n= m + 12
this is actually the same as (1)
n-m=12
12C12 = 1
Suff

D
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