varun289 wrote:307. Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?
A. 9:30
B. 9:00
C. 8:40
D. 7:50
E. 7:00
From 4:30 to 5:20, the number of pages read by Tom = r*t = 30(5/6) = 25.
From 5:20pm on, Jan COMPETES with Tom.
When elements compete, SUBTRACT THE RATES.
Jan's rate - Tom's rate = 40-30 = 10.
This is the CATCH-UP rate: the rate at which Jan CATCHES UP to Tom.
Because Jan reads 10 more pages than Tom every hour, she CATCHES-UP by 10 pages every hour.
Time for Jan to catch up by 25 pages = w/r = 25/10 = 2.5 hours.
Since Jan starts to read at 5:20pm, she catches-up to Tom at 5:20pm + 2:30 = 7:50pm.
The correct answer is
D.
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