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by bstalling » Sun Aug 30, 2009 6:07 pm
((2^(4-1))^2)/2^(3-2)

Where am I going wrong...
((2^(4-1))^2) = 2^(3*2) = 2^6/2^1 = 2^5

Sorry here are the answer choices
A 2^8
B 2^7
C 2^6
D 2^9
E 2^5

OA A
Last edited by bstalling on Mon Aug 31, 2009 5:40 am, edited 1 time in total.
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Source: — Problem Solving |

by bharathh » Sun Aug 30, 2009 8:24 pm
?

What are you supposed to get?

How about typing in the answer choices as well?
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by hbabbar » Mon Aug 31, 2009 1:23 am
Check out the solution

((2^(4-1))^2)/2^(3-2)

((2^3)^2)/2^1

(8^2)/2

64/2

Answer = 32
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by 2010gmat » Mon Aug 31, 2009 5:55 am
((2^(4-1))^2)/2^(3-2)

Where am I going wrong...
((2^(4-1))^2) = 2^(3*2) = 2^6/2^1 = 2^5

Sorry here are the answer choices
A 2^8
B 2^7
C 2^6
D 2^9
E 2^5
----------------------------------

Nr -- 2^(4-1)^2 = 2^3^2 --> its 2 raised to power 3 and 3 is raised to power 2 --> 2^9

and u have rightly solved the Dr

--> 2^9/2^1 = 2^8 == answer
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by hbabbar » Mon Aug 31, 2009 8:52 pm
srry guys there is some error with the brackets used in the ques... the answer to this ques is 2^5 only...

But if this ques is like this

(2^((4-1)^2)) -------- then the answer will be 2^9

check the ques again...
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