Integers: Knewton Prep

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by 6983manish » Thu Mar 31, 2011 1:12 am
rohu27 wrote:Hi Manish,
I completely get what the problem is aksing for and the explanations given have been more than useful
But I was just trying to tweak the question. the Q says the largest integer which much divide m but if the question asks for a largest integer which can divide m and gives the same options then what?

we know that m=4*sqrt(3k) so k can be 48 which makes m=48 and so m is divisible by 4(m^2 would be obviously divisible by 48 then)?
do let me know if im assuming somethng here. my point is both 12 and 16 qualify for answer choices, but the value which would always divide m(for any value) will be only 12.
Yes Rohu,

You are right , if we tweak the question this way , 16 would be the answer.

Sorry , I didn't notice you CAN ( in caps ) and just went with the problem flow.

Cheers Buddy.

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by lunarpower » Fri Apr 01, 2011 4:11 am
like most of knewton's questions, this one is essentially a carbon copy of one of GMAC's problems.

here's the original (from OG 10th edition):
https://www.urch.com/forums/gmat-problem ... 412-a.html
Ron has been teaching various standardized tests for 20 years.

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