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by theCodeToGMAT » Wed Oct 02, 2013 7:26 am
Area of AOC + Area of ABO
= √(10-1)/2 + √(10-1)/2
= √9
= 3

Answer [spoiler]{D}[/spoiler]
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by mevicks » Wed Oct 02, 2013 7:27 am
Image

In the figure above, line segments AB and AC are tangent to circle O. If the length of OB = 1 and the length of OA = √10, what is the area of quadrilateral ABOC? (Figure not drawn to scale.)

A. 3/2
B. √3
C. 2√2
D. 3
E. 2√3
Tangents to a circle from an external point meet at right angles, ABO and ACO are both 90 degrees.

In the right angled triangle OBA,
Image
Image
BA = 3

Thus area of the quadrilateral = Sum of the areas of the triangles OBA and OCA = 2*(1/2)*3*1 = 3

[spoiler]Answer : D[/spoiler]

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Vivek
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