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xtremecoder007
- Junior | Next Rank: 30 Posts
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Population of Country S is 10 million less than population of country J. If in 5 years, Country J has twice as many people, how many people will live in country S in 3 years given that each country has a constant population growth of 0.5 million people.
I understand this as below
Now - Today
Assume that Population in J = J
=> Population in S = J - 10.
After 5 Years
Population in J = J + 0.5 * 5 = J + 2.5
Population in S = J - 10 + 0.5 * 5 = J - 10 + 2.5
Given that, after 5 years population in J is double that of S
=> J + 2.5 = 2 ( J - 10 + 2.5 )
=> J = 7.5 ( After calcuation )
that means Population of J on current day is 7.5
but, it also means Population of S is 7.5 - 10. This is logically not possible.
Any thoughts on this.
I know that we need to find J + 0.5 *3 = 7.5 + 1.5 = 9.0, which is the official answer.
I think the question is not constructed properly, please provide your thoughts on this.
I want to be sure that I am not missing anything here.
Thanks for your time.
HK.
I understand this as below
Now - Today
Assume that Population in J = J
=> Population in S = J - 10.
After 5 Years
Population in J = J + 0.5 * 5 = J + 2.5
Population in S = J - 10 + 0.5 * 5 = J - 10 + 2.5
Given that, after 5 years population in J is double that of S
=> J + 2.5 = 2 ( J - 10 + 2.5 )
=> J = 7.5 ( After calcuation )
that means Population of J on current day is 7.5
but, it also means Population of S is 7.5 - 10. This is logically not possible.
Any thoughts on this.
I know that we need to find J + 0.5 *3 = 7.5 + 1.5 = 9.0, which is the official answer.
I think the question is not constructed properly, please provide your thoughts on this.
I want to be sure that I am not missing anything here.
Thanks for your time.
HK.
