The smallest number which when diminished by 14, is exactly divisible 24, 32, 36, 42 and 56 is:
(A)2015
(B) 2030
(C) 2016
(D)2420
(A)2015
(B) 2030
(C) 2016
(D)2420
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ASIDE: A lot of integer property questions can be solved using prime factorization.sgr21 wrote:The smallest number which when diminished by 14, is exactly divisible 24, 32, 36, 42 and 56 is:
(A)2015
(B) 2030
(C) 2016
(D)2420
For a number to be divisible by multiple divisor number, it must contain all the factors of the divisorssgr21 wrote:thank the correct answer is 2030
bt i didnt understand how and why we did this step?
So, 7x2x2x2x3x3 = 504
please explain
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