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Integer Diff

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by LalaB » Mon Dec 26, 2011 10:18 am
pemdas wrote:why you restrict the RHS to 9? The point is a multiplication of inequalities containing more than one inequality sign may not be admissible. We have to test each inequality.
oh god, u r right.

-2<a<3
3<b<4

ab is not -8<ab<9 , but -8<ab<12 (12=3*4 , i.e. max value of the 1st inequity * max value of the 2nd inequity)

thnx for the correction
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by ronnie1985 » Mon Dec 26, 2011 8:01 pm
6 is answer
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by karthikpandian19 » Tue Dec 27, 2011 9:43 pm
OA is 6
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