BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Coordinate Geometry Problem

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 207
Joined: Mon Oct 06, 2008 12:22 am
Location: India
Thanked: 5 times
Followed by:3 members

Coordinate Geometry Problem

by The Jock » Fri Jul 02, 2010 1:35 am
In the rectangular coordinate system below, the line y = x is
the perpendicular bisector of segment AB (not shown), and
the y-axis is the perpendicular bisector of segment BC (not
shown). If the coordinates of point A are (3,2), what are the
coordinates of point C?
(A) (-3,-2)
(B) (-2, 3)
(C) (3,-2)
(D) (2,-3)
(E) (2, 3)

Image
Thanks and Regards,
Varun
https://mbayogi.wordpress.com/
Top
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 392
Joined: Sun May 16, 2010 2:42 am
Location: Bangalore, India
Thanked: 116 times
Followed by:10 members
GMAT Score:770

by albatross86 » Fri Jul 02, 2010 2:25 am
The easiest way to solve this is to draw a scaled diagram and predict each point. Doing it algebraically may take too long for test day.

Attached is a scaled diagram.

By observation, you can see clearly that in one unit square of the graph, y = x forms the diagonal, and so the other diagonal (AB) would be perpendicular to it and A and B would be equidistant from the line y = x.

Similarly, for BC to be perpendicular to y-axis and equidistant from it, simply reflect B across the y-axis to get C (-2,3)

Pick B
Attachments
save.png
~Abhay

Believe those who are seeking the truth. Doubt those who find it. -- Andre Gide
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 207
Joined: Mon Oct 06, 2008 12:22 am
Location: India
Thanked: 5 times
Followed by:3 members

by The Jock » Fri Jul 02, 2010 2:32 am
Thanks a lot
Thanks and Regards,
Varun
https://mbayogi.wordpress.com/
Top
Post new topic Post Reply
• Page 1 of 1