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confused

by grandh01 » Sat Aug 11, 2012 4:55 pm
If w, x, y, and z are on-negative
integers, each less than 3, and w(3^3) +
x(3^2) + y(3) + z = 34, then w+z=
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

What does "on-negative integers" mean?

OA is C
Last edited by grandh01 on Sat Aug 11, 2012 5:31 pm, edited 1 time in total.
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by theCEO » Sat Aug 11, 2012 5:15 pm
grandh01 wrote:If w, x, y, and z are on-negative
integers, each less than 3, and w(33) +
x(3^2) + y(3) + z = 34, then w+z=
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

What does "on-negative integers" mean?
I think the statement should be w(33) +
x(32) + y(3) + z = 34
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by theCEO » Sat Aug 11, 2012 5:21 pm
w(33) + x(32) + y(3) + z = 34


if w = 0
x = 1, y = 0 and z = 2: w+z = 2

if w = 1
x = 0, y = 0 and z = 1: w+z = 2

[spoiler]ans = c[/spoiler]

All other choices produces values for w and z greater than 3 or negative
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