IMO D
Ok firstly dont freak out looking at such questions there is always a simple way to solve these questions.
In this question if you notice the denominator in each fraction has a similar pattern. Its the product of 2 raised to some value with 5 raised to some value.
Try to make the denominators equal in each case by finding the GCD for the fractions in order to make comparisons simple.
The GCD in this case is 2^4*5^3
Convert the denominator of each fraction in 2^4*5^3 form
(a). 6 / 2^2 *5 ^2
6*2^2*5/ 2^4*5^3
(b). 1 / 2 ^ 3 * 5 ^ 2
1*2*5/2^4*5^3
(c). 28 / 2 ^ 2 * 5 ^ 3
28*2^2/2^4*5^3
(d). 62 / 2 ^ 3 * 5 ^ 3
62*2/2^4*5^3
(e). 122 / 2 ^ 4 * 5 ^ 3
Now since the denominators are same just compare the numerators and select the fraction which has the highest numerator.
Numerators of each fraction will be
a) 6*4*5 = 120
b) 2*5 = 10
c) 28*2 = 56
d) 62*10 = 620
e) 122
Hence the ans is D
Ok this process looks very time consuming but it isnt once you understand the logic behind it. It barely took more than a minute to solve it this way.