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by pradeepkaushal9518 » Fri Sep 10, 2010 11:16 pm
Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
A SMALL TOWN GUY
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Source: — Data Sufficiency |

by anantbhatia » Sat Sep 11, 2010 12:10 am
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by pradeepkaushal9518 » Sat Sep 11, 2010 1:12 am
can u explain?
A SMALL TOWN GUY
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by anantbhatia » Sat Sep 11, 2010 1:24 am
By knowing speed of Wendy we only know how long it'll take her to reach the restaurant. There's no information about speed\time of Bob. Hence A & D ruled out.

For 2,
speed of wendy =w
Speed of Bob= w+1

Time Wendy had to wait= half an hour(constant) + time taken by Wendy - time taken by Bob
= const + 3/w - 3/(w+1). Insufficient to get a value.

We would have known the exact time if we had known the value of w. Hence combining, (C) gives us a result.
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