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1000 DS, Test 13,

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by jaheer » Sun Mar 18, 2007 1:54 am
Someone Help me with this.


13. Larry saves x dollars per month. Will Larry’s total savings one year from now exceed his present savings by at least $500 ? (Assume that there is no interest.)

(1) In 6 months Larry's total savings will be $900.
(2) In 3 months Larry's total savings will exceed his present savings by $150.

Thanks
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Source: — Data Sufficiency |
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by jayhawk2001 » Sun Mar 18, 2007 8:29 am
For this question, it is sufficient if we know x since 12*x will be the increment
from the present savings.

Let i be the present savings

1 - insufficient. i + 6x = 900. We don't know i and/or x

2 - sufficient. (i + 3x - i) = 150. So x = 50 and so 12x = 600 which is > 500

So, is the answer B ?
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by keepsmilinyaar » Wed Apr 04, 2007 7:12 am
Larry saves x dollars a month. .
Larry’s total savings one year from now would be 12x dollars in a year.

So 12x should be greater than 500.
So to find an answer we only need to know the value of x.

(1) In 6 months Larry's total savings will be $900.
6x = 900
x can be found out.

(2) In 3 months Larry's total savings will exceed his present savings by $150.
3x = 150
x can be found out..

I think we can find the answers from both the options.
I hope I am correct.
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by guynoor » Wed Apr 04, 2007 8:09 am
keepsmilinyaar wrote:Larry saves x dollars a month. .
Larry’s total savings one year from now would be 12x dollars in a year.

So 12x should be greater than 500.
So to find an answer we only need to know the value of x.

(1) In 6 months Larry's total savings will be $900.
6x = 900
x can be found out.

(2) In 3 months Larry's total savings will exceed his present savings by $150.
3x = 150
x can be found out..

I think we can find the answers from both the options.
I hope I am correct.
Thats true answer can be found from both 1 and 2 so both are alone sufficient.
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by guynoor » Wed Apr 04, 2007 8:11 am
guynoor wrote:
keepsmilinyaar wrote:Larry saves x dollars a month. .
Larry’s total savings one year from now would be 12x dollars in a year.

So 12x should be greater than 500.
So to find an answer we only need to know the value of x.

(1) In 6 months Larry's total savings will be $900.
6x = 900
x can be found out.

(2) In 3 months Larry's total savings will exceed his present savings by $150.
3x = 150
x can be found out..

I think we can find the answers from both the options.
I hope I am correct.
Thats true answer can be found from both 1 and 2 so both are alone sufficient though i am not sure as to the logic you use. I solved it in a different way.
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by jrdeshpande » Mon Jul 18, 2011 8:49 pm
My appologies for starting the old chain back but I have recently started solving all the DS questions from this forum.


If we go with this logic X comes to 150 in (1) and 50 in (2) which is contradictory. So this is not correct.

We don't know how much Larry's initial saving is and so need to calculate considering his initial saving as 'i'. The correct answer in B.
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by amit2k9 » Mon Jul 18, 2011 11:39 pm
B is sufficient as

p+3x - p = 150 giving x = 50 and p = 0.
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