a data from gmat club

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diebeatsthegmat: Legendary Member; Posts: 1119; Joined: Fri May 07, 2010 8:50 amFollowed by: 3 members; Thanked: 29 times

by diebeatsthegmat » Fri Jun 17, 2011 7:36 am

i solved this one by counting median of Deli A and B
for deli A: Ì£15+17+19)/3=17/1 kg
and for Deli B: (16+18+20)=18/1kg
surely can conclude which one costs more, 6 kg of DeliA or Deli B
can you please explain more?

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Source: Beat The GMAT — Data Sufficiency | Fri Jun 17, 2011 7:36 am

Frankenstein: Legendary Member; Posts: 1448; Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members; Location: India; Thanked: 375 times

by Frankenstein » Fri Jun 17, 2011 8:43 am

Hi,
As 6 kgs is bought at both Delis, lets see what the minimum and maximum values could be
For Deli A: minimum is 15*6 = 90, maximum is 19*6 = 114
For Deli B: minimum is 15*6= 96, maximum is 20*6 = 120

From(1): Ratio of a:p:s at Deli B = 2:7:2
so, money spent is (6/11)(2*16+7*18+2*20) = (6/11)(198) = 108
No info. about Deli A
From(2): Ratio of a:p:s at Deli A = 6:2:1
so, money spent is (6/9)(6*15+2*17+1*19)=(2/3)*143 = 95.33
this is less than the minimum price at Deli B
So, sufficient

Hence, B

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