a^3-a<0 ==> a(a^2-1)<0
1-a^2>0 ==> a^2-1<0
since from the 2nd stm we know that a^2-1<0 then a must be >0
answ is C
1-a^2>0 ==> a^2-1<0
since from the 2nd stm we know that a^2-1<0 then a must be >0
answ is C
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When we evaluate the two statements together, we may consider only values that satisfy both statements.prashant misra wrote:i thought the answer to be D but i mistook the question as it also includes real values.gmat guru i understood the statements individually but how come -1<x<1
I completely missed that! I don't believe it..GMATGuruNY wrote: A negative fraction won't work in statement 1 because a negative fraction raised to an odd power gets bigger: (-1/2)^3 = -(1/8), and -1/8 > - 1/2.
So to satisfy both statements, 0 < a < 1. Sufficient.
The correct answer is C.
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