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A business bought R typewriters at $100 per typewriter and S

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by sethids » Mon Jul 14, 2008 8:43 am
From the question stem, we need to find the value of 100R + 50S.

Statement1: 50S = 200 => S = 4. No information about R so its insufficient. Left with option B, C and E.
Statement2: 2R+S = 10 is a eqn with 2 unknowns. The information from the stem does not help. So its also insufficient. Left with option C and E.

Substituting the value of S = 4 from statement 1 into eqn in statement 2 gives R = 3. Now total cost can be found.

Hence C.
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by mim3 » Mon Jul 14, 2008 11:43 am
sethids wrote:From the question stem, we need to find the value of 100R + 50S.

Statement1: 50S = 200 => S = 4. No information about R so its insufficient. Left with option B, C and E.
Statement2: 2R+S = 10 is a eqn with 2 unknowns. The information from the stem does not help. So its also insufficient. Left with option C and E.

Substituting the value of S = 4 from statement 1 into eqn in statement 2 gives R = 3. Now total cost can be found.

Hence C.
I could be wrong, but I think the answer is B.

From the stem, we know we're looking for 100R + 50S. Factoring out 50, we get: 50(2R + S). So we just need to find the value of 2R + S which the second statement provides.
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by sethids » Tue Jul 15, 2008 3:18 am
mim3 wrote:
sethids wrote:From the question stem, we need to find the value of 100R + 50S.

Statement1: 50S = 200 => S = 4. No information about R so its insufficient. Left with option B, C and E.
Statement2: 2R+S = 10 is a eqn with 2 unknowns. The information from the stem does not help. So its also insufficient. Left with option C and E.

Substituting the value of S = 4 from statement 1 into eqn in statement 2 gives R = 3. Now total cost can be found.

Hence C.
I could be wrong, but I think the answer is B.

From the stem, we know we're looking for 100R + 50S. Factoring out 50, we get: 50(2R + S). So we just need to find the value of 2R + S which the second statement provides.
Good point.... I missed that. I'll also go for B in that case.

Thanks.
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