help!!!
If 0<x<y, what is the value of (x+y)^2 / (x-y)^2?
(i) x^2 + y^2 = 3xy
(ii) xy = 3
answer A.
If 0<x<y, what is the value of (x+y)^2 / (x-y)^2?
(i) x^2 + y^2 = 3xy
(ii) xy = 3
answer A.
Expand (x+y)^2 = x^2+y^2 + 2xy
(x-y)^2 = x^2+y^2-2xy
We need to find : x^2+y^2 + 2xy / x^2+y^2-2xy
Stmt I
x^2 + y^2 = 3xy
So what we need to find becomes 3xy+2xy/ 3xy-2xy
xy's cancel and we can get to the value(5)
SUFF
Stmt II
xy=3
We know y in terms of x or x is terms of y but we cant find the value.
INSUFF
Choose A
