A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continue to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?
1.6 2/3
2.15
3.20
4.25
5.26 2/3
Rate and time are RECIPROCALS.
The RATE RATIO = hiker : cyclist = 4:20 = 1:5.
Thus, the TIME RATIO = hiker : cyclist = 5:1.
The implication is that the hiker will take 5 TIMES AS LONG as the cyclist to travel the same distance.
Thus, when the cyclist passes the hiker, the hiker will then require 25 minutes to travel the number of miles traveled by the cyclist in 5 minutes.
Time difference = hiker's time - cyclist's time = 25-5 = 20 minutes.
Thus, the cyclist will have to wait 20 minutes for the hiker to catch up.
The correct answer is
C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
