(1) The probability of drawing one blue marble is 6/35 .
(2) The probability of drawing no blue marbles is 4/35 .

What is the probability of drawing at least two blue marbles from a jar if three marbles are chosen?\

A.The probability of drawing one blue marble is .

B.The probability of drawing one blue marble is .

C.BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D.EACH statement ALONE is sufficient.

E.Statements (1) and (2) TOGETHER are NOT sufficient.

OA C

Bu my choice is D

From Statement A:

It is given the probability of drawing blue marble which is 6/35. From here we can find the probability of not drawing blue marble is 1-6/35=29/35

so from here we can find the probability at least two blue marbles from a jar if three marbles are chosen.

6/35*6/35*29/35 + 6/35*6/35*6/35

so statement A is sufficient

From Statement B:

The probability of drawing no blue marbles is 4/35. From here we can find the probability of drawing blue marble which is 1-4/35=31/35

So from here we can find the probability of at least two blue marbles from a jar if three marbles are chosen

So statement B is sufficient.

Therefore each statement is sufficient.

Please explain me where I am wrong!!