BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Equation - need expert help

Expert replies
by voodoo_child » Sun Sep 02, 2012 10:22 am
Why does this equation have infinite solutions ? I am not able to figure out why. Thoughts?

nc = (n+10) (c-15).... (i)
nc = (n-10)(c+15) ..... (ii)

The solution is 3n = 2c. However, when you substitute the values, you get weird ...-150 = 0!

Source - GMATClub

Thoughts...I am too much engrossed the problem that I can't think of a reason. Another perspective will help. I think it's something related to circular properties we did in JEE ...can't think of it right now....


Thanks
Join the discussion
Source: — Problem Solving |

by rijul007 » Sun Sep 02, 2012 11:41 am
THe two equations are not the equations of a circle.

SImplify equation (i)
nc = (n+10)(c-15)
nc = nc +10c - 15n -150
10c -15n = 150 (which is a straight line)

similarly for equation (ii)
nc = (n-10)(c+15)
nc = nc -10c +15n -150
-10c + 15n = 150 (also a straight line)

Since the two lines have the same slope, the two lines are parellel to each other.
Hence, they have no solution.
Join the discussion

by voodoo_child » Sun Sep 02, 2012 1:17 pm
rijul007 wrote:THe two equations are not the equations of a circle.
Oh thanks .... You are correct the equations are parallel. When I said "circular properties", I didn't mean equation of circle.[:D] ....circular properties are when, as you said, the slope is same, OR for instance, if the unique solution to the equation is x= 3; y= 2 then multiplying the equations with an integer will result in the integral multiples, for instance 3x = 9 and 3y=6. There is an OG question on this concept.

I think that it was in Bernard and Child book...any way thanks....My mind was too much exhausted :(
Join the discussion