BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Points and Hieght

Expert replies
by GMATPR » Tue Apr 22, 2008 7:03 am
Please explain this for me. Thanks


The (x, y) coordinates of points P and Q are (-2, 9) and (-7, -3), respectively. The height of equilateral triangle XYZ is the same as the length of line segment PQ. What is the area of triangle XYZ?
Join the discussion
Source: — Problem Solving |

by AleksandrM » Tue Apr 22, 2008 9:57 am
I've only been able to arrive at the height of the triangle, which is 13.

This triangle will obviously have angles 60:60:60, and all three sides will be equal... hence, equilateral.

You can split the triangle into two right angle triangles with base 13, but we will then need one of the other two heights. The triangle will be 90:60:30 with sides x:xroot3:2x.

The answer might be 169sqroot3.

Hope someone can take this further.
Join the discussion

by Stuart@KaplanGMAT » Tue Apr 22, 2008 10:50 am
AleksandrM wrote:I've only been able to arrive at the height of the triangle, which is 13.

This triangle will obviously have angles 60:60:60, and all three sides will be equal... hence, equilateral.

You can split the triangle into two right angle triangles with base 13, but we will then need one of the other two heights. The triangle will be 90:60:30 with sides x:xroot3:2x.

Hope someone can take this further.
You're almost there!

The height of an equliateral triangle is the xroot3 side of the 30/60/90 triangle.

To calcuate the area of the triangle, we also need the base - so, we need to solve for x.

xroot3 = 13
x = 13/root3

The base of the equilateral triangle is actually the 2x side (since every side is the same), so the base is 2*(13/root3) or 26/root3

Area = 1/2 * base * height
Area = 1/2 (26/root3) (13)
Area = 169/root3

If that appears among the answers, we're done. However, most GMAT answer choices "rationalize the denominator", which basically means getting rid of the root. To do so, we multiply the top and bottom of the fraction by the root itself.

169/root3 = 169(root3)/root3(root3) = 169root3/3

In all likelihood, that's the actual correct answer.
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

by GMATPR » Tue Apr 22, 2008 12:17 pm
Thanks AleksandrM and Stuart, I understand this now.
Join the discussion