Solution:
We have 2+4+6+8.....100 = 2550.
We need the value of 102+104+106..200 = (100+2)+(100+4)+(100+6)...+(100+100)
= 100*50 + (2+4+6...100) = 5000+2550 = 7550.
The correct answer is hence (B).
PS: Integers problem..
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Another way to approach this problem is by using the average of the set * the number of items in the set. To find the average, just add 200+102=302/2=151. Then to find the number of even numbers: 200-102=98/2(divide by 2 so you only count the even numbers) = 49, then you always add 1 when counting, thus =50. Now you multiply 50*151=7550.
