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Yes/No DS

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Yes/No DS

by sakurle » Fri Aug 21, 2009 7:19 pm
Is 1/p > r/(r.sq + 2)

1. p = r
2. r > 0

(By the way how to type r raised to 2 or r-square)
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by iamjakekim » Fri Aug 21, 2009 8:07 pm
C

STM1. Since P=r, they can be either - or +, thus INS.

STM2. R = + does not say much either INS.

1+2 gives us that p=r and both are +.

Simplify it, and we get 1 > (r^2)/(r^2+2) hence YES !!
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