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If x and y are positive integers, does x/y = 7/9?

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by M7MBA » Wed May 23, 2018 4:44 am

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If x and y are positive integers, does x/y = 7/9?

(1) x = 103
(2) 11/13 < x/y < 8/9

The OA is the option D.

Why is sufficient each statement alone? I couldn't solve this DS question. Help!!! <i class="em em-neutral_face"></i>
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Source: — Data Sufficiency |

by GMATGuruNY » Wed May 23, 2018 5:10 am
M7MBA wrote:If x and y are positive integers, does x/y = 7/9?

(1) x = 103
(2) 11/13 < x/y < 8/9
Statement 1:
Test whether it's possible that x/y = 7/9 when x=103:
103/y = 7/9
7y = 103*9
y = (103*9)/7 = noninteger.
Since y must be a positive integer, it is not possible that x/y = 7/9.
Thus, the answer to the question stem is NO.
SUFFICIENT.

To compare fractions:
1. Multiply the numerator in each fraction by the denominator in the OTHER fraction
2. The numerator that yields the greater product belongs to the bigger fraction

Statement 2:
Compare 7/9 to 11/13:
7*13 = 91.
11*9 = 99.
Since the numerator of 11/13 yields the greater product, 11/13 > 7/9.
Thus, statement 2 implies the following:
7/9 < 11/13 < x/y < 8/9.
The resulting inequality indicates that x/y ≠ 7/9.
Thus, the answer to the question stem is NO.
SUFFICIENT.

The correct answer is D.
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