sivaelectric wrote:If x is an integer, is y an integer?
1) (4X+4Y)/2 = 6
2) (3X+6Y)/3 = 5
Target question: Is y an integer?
Given: x is an integer
Statement 1: (4x + 4y)/2 = 6
Multiply both sides by 2 to get: 4x + 4y = 12
Divide both sides by 4 to get:
x + y = 3
Since x is an INTEGER and 3 is an INTEGER, we can rewrite the above equation as INTEGER + y = INTEGER
From this, we can conclude that
y must be an integer
Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: (3x + 6y)/3 = 5
Multiply both sides by 3 to get: 3x + 6y = 15
Divide both sides by 3 to get:
x + 2y = 5
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 1 and y = 2, in which case
y IS an integer
Case b: x = 2 and y = 1.5, in which case
y is NOT an integer
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
Cheers,
Brent