how to solve this exponent problem from the gmat Prep

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by Anurag@Gurome » Mon Sep 26, 2011 6:24 pm
Taniuca wrote:(10^8-10^2)/(10^7-10^3)
10^2(10^6 - 1)/10^3(10^4 - 1) = (10^6 - 1)/[10(10^4 - 1)]
Now 10^6 - 1 is approx 10^6, and 10^4 - 1 is approx 10^4.
So, we get 10^6/10(10^4) = 10^6/10^5 = 10
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by Bigred2008 » Wed Sep 28, 2011 11:41 am
Anurag@Gurome wrote:
Taniuca wrote:(10^8-10^2)/(10^7-10^3)
10^2(10^6 - 1)/10^3(10^4 - 1) = (10^6 - 1)/[10(10^4 - 1)]
Now 10^6 - 1 is approx 10^6, and 10^4 - 1 is approx 10^4.
So, we get 10^6/10(10^4) = 10^6/10^5 = 10
I wanted to ask a question about this line "(10^6 - 1)/[10(10^4 - 1)] " after you factor 10^2 out of the numerator and then 10^3 out of the denominator, why does the denominator become (10(10^4-1)) what happened to the exponent of 3? I see you subtracted the 10^2 from the 10^3, but shouldn't that leave 10^-1 rather than a positive number?
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