I believe (based on the OA) that the question should read as follows:

manik11 wrote:If x and n are integers such that x = 1² + 2² + 3² + . . . + n², what is the remainder when x is divided by 5?

(1) n is an even integer with a units digit less than 6.
(2) The units digit of n is 2.

OA : D

Target question: What is the remainder when x is divided by 5?

Given: x = 1² + 2² + 3² + . . . + n²
Before we examine each statement, let's TEST some values of n to see if there's a PATTERN.
n = 1: x = 1² = 1. So, when x is divided by 5, the remainder is 1
n = 2: x = 1² + 2² = 5. So, when x is divided by 5, the remainder is 0
n = 3: x = 1² + 2² + 3² = 14. So, when x is divided by 5, the remainder is 4
n = 4: x = 1² + 2² + 3² + 4² = 30. So, when x is divided by 5, the remainder is 0
n = 5: x = 55. So, when x is divided by 5, the remainder is 0
n = 6: x = 91. So, when x is divided by 5, the remainder is 1
n = 7: x = 140. So, when x is divided by 5, the remainder is 0
n = 8: x = 204. So, when x is divided by 5, the remainder is 4
n = 9: x = 285. So, when x is divided by 5, the remainder is 0
n = 10: x = 385. So, when x is divided by 5, the remainder is 0
n = 11: x = 506. So, when x is divided by 5, the remainder is 1
n = 12: x = 650. So, when x is divided by 5, the remainder is 0
n = 13: x = 819. So, when x is divided by 5, the remainder is 4
n = 14: x = 1015. So, when x is divided by 5, the remainder is 0
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Aha, so the pattern repeats itself every 5 instances.
So, the remainder when n = 3 is the same as the remainder when n = 8, 13, 18, 23, etc
Likewise, the remainder when n = 4 is the same as the remainder when n = 9, 14, 19, 24, etc

Statement 1: n is an even integer with a units digit less than 6.
In other words, the units digit of n is 0, 2 or 4
From our calculations above, we can conclude that when we divide x by 5, the remainder will be 0
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: The units digit of n is 2.
From our calculations above, we can conclude that when we divide x by 5, the remainder will be 0
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

Cheers,
Brent