Gmat_mission wrote: ↑Thu Aug 27, 2020 8:10 am
If \(y = x^2 - 6x + 9,\) what is the value of \(x?\)
(1) \(y = 0\)
(2) \(x + y = 3\)
Answer:
A
Source: Official Guide
Solution:
Question Stem Analysis:
We need to determine the value of x.
Statement One Alone:
Since y = 0, we can solve the equation:
x^2 - 6x + 9 = 0
(x - 3)^2 = 0
x - 3 = 0
x = 3
Statement one alone is sufficient.
Statement Two Alone:
Since x + y = 3, y = 3 - x and we can solve the equation:
x^2 - 6x + 9 = 3 - x
x^2 - 5x + 6 = 0
(x - 3)(x - 2) = 0
x = 3 or x = 2
Since x can be either 3 or 2, statement two alone is not sufficient.
Answer: A
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