This is a common question type on the GMATAshetty wrote: [1001^2 - 999^2] / [101^2 - 99^2]= 10 (How??)
It requires you to factor the difference of squares in the numerator and denominator.
Aside: a^2 - b^2 = (a+b)(a-b)
[1001^2 - 999^2] / [101^2 - 99^2]
= [(1001+999)(1001-999)] / [(101+99)(101-99)]
=[(2000)(2)] / [(200)(2)]
=[4000] / [400]
= 10
Cheers,
Brent













