If \(N\) is a positive integer, what is the last digit of \(1! + 2! + \cdots +N!?\)

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If \(N\) is a positive integer, what is the last digit of \(1! + 2! + \cdots +N!?\)

(1) \(N\) is divisible by \(4.\)
(2) \(\dfrac{N^2 + 1}5\) is an odd integer.

Answer: D

Source: GMAT Club Tests
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