I'm assuming that the periods in your post are meant to represent multiplication.
I have replaced the periods with "x"
Please go back and edit your original post.
alanforde800Maximus wrote:Let f(n) = the number of distinct factors n has. For example, f(20) = 6, because 20 has six factors(1,2,4,5,10 and 20). Which of the following products is equal to 225?
a) f(10) x f(100)
b) f(100) x f(1000)
c) f(1000) x f(10000)
d) f(100) x f(10000)
e) f(10) x f(1000)
NICE RULE
If N = (p^a)(q^b)(r^c)..., where p, q, r,...(etc.) are prime numbers, then the total number of positive divisors of N is equal to (a+1)(b+1)(c+1)...
Example: 14000 = (2^
4)(5^
3)(7^
1)
So, the number of positive divisors of 14000 = (
4+1)(
3+1)(
1+1) = (5)(4)(2) = 40
----------------------------------------
Let's test a few values:
100 = (2^
2)(5^
2)
So, the number of positive divisors of 100 = (
2+1)(
2+1) = (3)(3) = 9
So, f(100) = 9
1000 = (2^
3)(5^
3)
So, the number of positive divisors of 1000 = (
3+1)(
3+1) = (4)(4) = 16
So, f(1000) = 16
10000 = (2^
4)(5^
4)
So, the number of positive divisors of 10000 = (
4+1)(
4+1) = (5)(5) = 25
So, f(10000) = 25
Which of the following products is equal to 225?
225 = 9 x 25
= f(100) x f(10000)
Answer:
D
RELATED RESOURCES
- Counting the divisors of large number:
https://www.gmatprepnow.com/module/gmat ... /video/828
- Prime factorization:
https://www.gmatprepnow.com/module/gmat ... /video/825