An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

by BTGmoderatorDC » Wed Nov 03, 2021 6:42 am

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An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5

OA D

Source: Manhattan Prep

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Source: Beat The GMAT — Problem Solving | Wed Nov 03, 2021 6:42 am

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8152; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

Re: An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How

by Scott@TargetTestPrep » Fri Nov 05, 2021 7:46 am

BTGmoderatorDC wrote: ↑
Wed Nov 03, 2021 6:42 am
An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5

OA D

Source: Manhattan Prep

We can create the proportion:

6/(7/10) = n/(3/10)

60/7 = 10n/3

180 = 70n

180/70 = n

18/7 = n

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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swerve: Legendary Member; Posts: 2545; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How

by swerve » Sat Nov 06, 2021 6:38 pm

BTGmoderatorDC wrote: ↑
Wed Nov 03, 2021 6:42 am
An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5

OA D

Source: Manhattan Prep

Suppose, capacity $= 70 .$
So, to fill $\dfrac{7}{10}$ of $70$ i.e. $49,$ it took $6$ minutes.

Hence, to fill $70$ it will take $= 10\ast \dfrac{6}{7} = \dfrac{60}{7}$ minutes.

So, additional time $= \dfrac{60}{7} - 6 = \dfrac{18}{7} \Longrightarrow $ D

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