In the standard (x,y) coordinate plane, what is the slope of

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by Brent@GMATPrepNow » Wed Dec 25, 2019 7:16 am
BTGmoderatorDC wrote:In the standard (x,y) coordinate plane, what is the slope of the line containing the distinct points P and Q ?

(1) Both P and Q lie on the graph of |x| + |y| = 1.
(2) Both P and Q lie on the graph of |x + y| = 1.
Target question: What is the slope of the line containing the distinct points P and Q ?

Statement 1: Both P and Q lie on the graph of |x| + |y| = 1
Since most people aren't familiar with the graph of |x| + |y| = 1, it makes sense to test some values
There are infinitely many values of x and y that satisfy statement 1. Here are two:
Case a: For point P, x = 1 and y = 0 (1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - 1) = -1
Case b: For point P, x = -1 and y = 0 (-1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - -1) = 1
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: Both P and Q lie on the graph of |x + y| = 1
Before we do anything else, let's first check to see whether we can re-test the same values we used to show that statement 1 is not sufficient.
Yes, it turns out that we CAN re-use those same values to get:
Case a: For point P, x = 1 and y = 0 (1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - 1) = -1
Case b: For point P, x = -1 and y = 0 (-1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - -1) = 1
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Since we were able to use the same counter-examples to show that each statement ALONE is not sufficient, the same counter-examples will satisfy the two statements COMBINED.
In other words,
Case a: For point P, x = 1 and y = 0 (1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - 1) = -1
Case b: For point P, x = -1 and y = 0 (-1,0) and, for point Q, x = 0 and y = 1 (0,1). In this case, the slope of the line = (1 - 0)/(0 - -1) = 1
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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