hi,lee3381 wrote:2(x^2 - 9) / (x^2 + x - 6) + 2/(x-2) = ?
The answer is 2.
Can anyone explain this answer?
first let me factorize different equations ..
(x^2 - 9)=(x-3)(x+3)...
(x^2 + x - 6)= x^2+3x-2x-6=x(x+3)-2(x+3)=(x-2)(x+3)..
now lets substitute these values in main equation..
2(x^2 - 9) / (x^2 + x - 6) + 2/(x-2)..
2(x-3)(x+3) / (x-2)(x+3) + 2/(x-2)=2(x-3)/(x-2) + 2/(x-2)...
{2(x-3)+2}/(x-2) = (2x-6+2)/(x-2)..
(2x-4)/(x-2)= 2(x-2)/(x-2)=2..
Hope it helps .
