BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

On a Monday in a certain restaurant, 20 percent of the 180

Expert replies
by BTGmoderatorDC » Mon Aug 19, 2019 4:27 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

OA B

Source: Veritas Prep
Join the discussion
Source: — Problem Solving |

by Jay@ManhattanReview » Mon Aug 19, 2019 7:57 pm
BTGmoderatorDC wrote:On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

OA B

Source: Veritas Prep
"¢ # of customers ordered special on Monday = 12% of 180 = 36;
"¢ # of customers ordered special on Tuesday = 10% of 120 = 12

Total # of customers who ordered special on both days = 36 + 12 = 48;
Total # of customers on both days = 180 + 120 = 300;

Percent of the customers ordered the daily special = (48/300)*100% = 16%

The correct answer: B

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: GMAT Classes Oxford | GMAT Prep Courses Bangalore | LSAT Prep Courses Atlanta | Manhattan SAT | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion

by Scott@TargetTestPrep » Sun Aug 25, 2019 5:30 pm
BTGmoderatorDC wrote:On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

OA B

Source: Veritas Prep
On the first day, 0.2 x 180 = 36 customers ordered the special.

On the second day, 0.1 x 120 = 12 ordered the special.

We combine the data for the two days. Thus, (36 + 12)/(180 + 120) = 48/300 = 0.16 = 16% of the customers ordered the special.

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion

by Brent@GMATPrepNow » Mon Aug 26, 2019 6:05 am
BTGmoderatorDC wrote:On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

OA B

Source: Veritas Prep
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special.
10% of 180 = 18
So, 20% of 180 = 36
So, 36 people ordered the daily special on MONDAY

On Tuesday, only 10 percent of the 120 customers ordered the special.
10% of 120 = 12
So, 12 people ordered the daily special on TUESDAY

For the two days combined, what percent of the customers ordered the daily special?
TOTAL number of people who ordered the daily special = 36 + 12 = 48 people
TOTAL number of customers for the two days = 180 + 120 = 300

So 48/300 of the customers ordered the special.
Our job is to rewrite 48/300 as a PERCENT. Here's one approach:
Take: 48/300
Divide top and bottom by 3 to get the EQUIVALENT fraction 16/100
16/100 = 16%

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion