From a total of 5 boys and 4 girls, how many 4-person...

BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

This topic has expert replies

Post new topic Post Reply

Previous Topic Next Topic

swerve: Legendary Member; Posts: 2499; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

From a total of 5 boys and 4 girls, how many 4-person...

by swerve » Fri Jan 12, 2018 1:45 pm

From a total of 5 boys and 4 grils, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

(A) 16
(B) 24
(C) 60
(D) 120
(E) 240

The OA is C.

Please, can any expert explain this PS question for me? I can't get the correct answer. I need your help. Thanks.

Quote

Source: Beat The GMAT — Problem Solving | Fri Jan 12, 2018 1:45 pm

GMATWisdom: Master | Next Rank: 500 Posts; Posts: 100; Joined: Wed Nov 29, 2017 4:38 pm; Thanked: 14 times

by GMATWisdom » Fri Jan 12, 2018 2:55 pm

swerve wrote:From a total of 5 boys and 4 grils, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

(A) 16
(B) 24
(C) 60
(D) 120
(E) 240

The OA is C.

Please, can any expert explain this PS question for me? I can't get the correct answer. I need your help. Thanks.

2 boys can be selected from 5 boys in 5c2ways=10
2girls can be selected from 4 girls in 4c2 ways=6
therefore 2 boys and 2 girls can be selected in 10x6=60ways
Option C

Quote

GMAT/MBA Expert

Scott@TargetTestPrep: GMAT Instructor; Posts: 8086; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

by Scott@TargetTestPrep » Tue Aug 06, 2019 4:33 pm

swerve wrote:From a total of 5 boys and 4 grils, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

(A) 16
(B) 24
(C) 60
(D) 120
(E) 240

The OA is C.

Please, can any expert explain this PS question for me? I can't get the correct answer. I need your help. Thanks.

We can select 2 girls in 4C2 = (4 x 3)/2! = 6 ways.

We can select 2 boys in 5C2 = (5 x 4)/2! = 10 ways.

Thus, the group can be formed in a total of 6 x 10 = 60 ways.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]