Modulus inequality --Veritas question
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GMATGuruNY
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I posted a solution here: https://www.beatthegmat.com/value-of-x-t268225.html
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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Jeff@TargetTestPrep
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Let's first solve for when (12x - 5) and (7 - 6x) are both positive.Mo2men wrote:If |12x−5|>|7−6x|, which of the following CANNOT be the product of two possible values of x?
A. -12
B. -7/5
C. -2/9
D. 4/9
E. 17
12x - 5 > 7 - 6x
18x > 12
x > 12/18
x > 2/3
Now let's solve for when (12x - 5) is negative and (7 - 6x) is positive.
-(12x - 5) > 7 - 6x
-12x + 5 > 7 - 6x
-2 > 6x
-1/3 > x
So we have x < -1/3 or x > 2/3.
If x were -1/3 or 2/3, then the product would be -2/9. However, the inequalities specify that x can be neither -1/3 nor 2/3, so we know the product of two possible values of x cannot be -2/9.
Answer: C
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