BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

The integers v, w, x, y and z are such that 0 < v < w

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 41
Joined: Wed Oct 30, 2019 1:10 pm
by ktrout2020 » Wed Nov 06, 2019 2:51 pm
The integers v, w, x, y and z are such that 0 < v < w < x < y < z. The average of these integers is 36 and median of these 5 integers is 28. What is the greatest possible value of Z?

a) 128
b) 130
c) 140
d) 132
e) 120

Source: Veritas
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members
Location: Grand Central / New York
Thanked: 470 times

by Jay@ManhattanReview » Wed Nov 06, 2019 11:56 pm
ktrout2020 wrote:The integers v, w, x, y and z are such that 0 < v < w < x < y < z. The average of these integers is 36 and median of these 5 integers is 28. What is the greatest possible value of Z?

a) 128
b) 130
c) 140
d) 132
e) 120

Source: Veritas
So, we have all the positive integers with median = x = 28, the middle-most integer. Let's assign the minimum possible values for v, x and y so that we have the greatest possible value of z. Minimum value of v = 1, w = 2 and y = 29 (1 greater than x).

Thus, the sum of v, w, x, y and z = 1 + 2 + 28 + 29 + z = 36*5 => z = 120

The correct answer: E

Hope this helps!

-Jay
_________________
Manhattan Review

Locations: Manhattan Review Mumbai | GMAT Prep New Delhi | GRE Prep Malleswaram | Vijayawada GRE Coaching | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Mon Nov 11, 2019 9:26 am
ktrout2020 wrote:The integers v, w, x, y and z are such that 0 < v < w < x < y < z. The average of these integers is 36 and median of these 5 integers is 28. What is the greatest possible value of Z?

a) 128
b) 130
c) 140
d) 132
e) 120

Source: Veritas
The average of these integers is 36
So, (v + w + x + y + z)/5 = 36
So, v + w + x + y + z = 180

The median of these 5 integers is 28
Since x is the middlemost value (in ascending order), we know that x = 28
So, we have v, w, 28, y, z

If we want to MAXIMIZE the value of z, we must MINIMIZE the remaining values.
Since v is a positive integer, the smallest value of v is 1
1, w, 28, y, z

Since v < w, the smallest value of w is 2
1, 2, 28, y, z

Since x < y, the smallest value of y is 29
1, 2, 28, 29, z

Since v + w + x + y + z = 180, we know that 1 + 2 + 28 + 29 + z = 180
Simplify: 60 + z = 180
z = 120

Answer: E

RELATED VIDEO FROM MY COURSE
- Mean, median and mode: https://www.gmatprepnow.com/module/gmat ... /video/800
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8138
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

by Scott@TargetTestPrep » Tue Nov 12, 2019 7:13 pm
ktrout2020 wrote:The integers v, w, x, y and z are such that 0 < v < w < x < y < z. The average of these integers is 36 and median of these 5 integers is 28. What is the greatest possible value of Z?

a) 128
b) 130
c) 140
d) 132
e) 120

Source: Veritas
We are given that the average of v, w, x, y, and z is 36. Using the formula average = sum/number, we get:

36 = sum/5

180 = sum

We are also given that the median is 28 and need to determine the greatest value of z.

To maximize the value of a single number, we minimize the values of all the other numbers, in accordance with any constraints.

v = 1

w = 2

x = 28 = median

y = 29

Thus, v + w + x + y = 1 + 2 + 28 + 29 = 60. So, the largest possible value of z is 180 - 60 = 120.

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1