If a, b, c, d are 4 non-negative integers. Is (a+c) even?

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Source: — Data Sufficiency |

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by Jay@ManhattanReview » Tue Feb 12, 2019 8:48 pm

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AAPL wrote:e-GMAT

$$\text{If } a, b, c, d \text{ are 4 non-negative integers. Is } (a+c) \text{ even?}$$
$$1.\ a^2+b^2+c^2\ \text{ is even.}$$
$$2.\ b^2+c^2+d^2\ \text{ is even.}$$
OA E
Given: a, b, c, d are 4 non-negative integers.

We have to determine whether (a + c) is even.

Let's take each statement one by one.

(1) a^2 + b^2 + c^2 is even.

Case 1: Say a = 0; b = c = 1, then we have a^2 + b^2 + c^2 = 0^2 + 1^2 + 1^2 = 2, an even number. However, a + c = 0 + 1 = 1, an odd number; the answer is no.

Case 2: Say b = 0; a = c = 1, then we have a^2 + b^2 + c^2 = 1^2 + 0^2 + 1^2 = 2, an even number. We see that a + c = 1 + 1 = 2, an even number; the answer is yes.

No unique answer. Insufficient.

(2) b^2 + c^2 + d^2 is even.

No information about a. Insufficient.

(1) and (2) together

Even after combining the two statements, both the cases discussed in Statement 1 are applicable. Insufficient.

The correct answer: E

Hope this helps!

-Jay
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