What is the value of xyz?

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What is the value of xyz?

by Max@Math Revolution » Wed Sep 25, 2019 11:22 pm
[GMAT math practice question]

What is the value of xyz?

1) x+ 1/y = 2
2) y - 1/z = 1/2
Source: — Data Sufficiency |

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by deloitte247 » Fri Sep 27, 2019 11:40 pm
We are looking for the product of x, y, and z.
$$Statement\ 1=>x+\frac{1}{y}=2$$
$$x=2-\frac{1}{y}=\frac{2y-1}{y}$$
$$or\ xy=2y-1$$
Value of z is unknown here, hence, statement 1 is NOT SUFFICIENT.

$$Statement\ 2=>y-\frac{1}{z}=\frac{1}{2}$$
$$y=\frac{1}{2}+\frac{1}{z}=\frac{z+2}{2z}$$
Since, there is no reference to 'x', it is safe to conclude that statement 2 is INSUFFICIENT.

Combining both statements together
$$x=\frac{2y-1}{y};\ y=\frac{z+2}{2z}$$
To get Z,
$$y-\frac{1}{z}=\frac{1}{2}$$
$$-\frac{1}{z}=\frac{1-2y}{2}$$
$$z=-\frac{2}{1-2y}$$
$$Therefore,\ xyz=\left(\frac{2y-1}{y}\right)\left(\frac{z-2}{2z}\right)\left(-\frac{2}{1-2y}\right)$$
$$=\frac{\left(2y-1\right)\left(z-2\right)\left(-2\right)}{\left(y\right)\left(2z\right)\left(1-2y\right)}$$
$$=\frac{\left(2y-1\right)\left(-2z+4\right)}{\left(2yz\right)\left(1-2y\right)}$$
$$=\frac{-4yz+8y+2z-4}{2yz-4y^2z}$$
This does not give the exact value of the product xyz. Hence, both statements combined together are NOT SUFFICIENT.

Answer = option E

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by Max@Math Revolution » Sun Sep 29, 2019 5:15 pm
=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have 3 variables (x, y and z) and 0 equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

Since x + 1/y = 2, we have x = 2 - 1/y = (2y-1)/y.
Since y - 1/z = 1/2, we have 1/z = y - 1/2 = (2y-1)/2 or z = 2/(2y-1).
Then we have xyz = [(2y-1)/y]*y*[2/(2y-1)] = 2.
Since both conditions 1) & 2) together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with "3 variables", or "4 variables and 1 equation", or "5 variables and 2 equations", conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.