In a survey of parents, exactly 3/4 of the mothers and 9/10

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In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs?

A. 27%
B. 21%
C. 19%
D. 18%
E. 16%

[spoiler]OA=E[/spoiler]

Source: Princeton Review
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by Brent@GMATPrepNow » Mon Nov 25, 2019 6:49 am
M7MBA wrote:In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs?

A. 27%
B. 21%
C. 19%
D. 18%
E. 16%
Since we are asked to find a PERCENT (and not an actual value), let's choose a nice value for the total number of parents.

Let 100 = the total number of parents

Number of mothers = 40% of 100 = 40
Number of fathers = 60% of 100= 60

Number of mothers WITH full-time job = 3/4 of 40 = 30
Number of fathers WITH full-time job = 9/10 of 60 = 54
Total number of parents with full-time job = 30 + 54 = 84

Thus parents without full time job = 100 - 84 = 16
So, 16 of the 100 parents do not have full-time jobs.
In other words, 16% of them do not have full-time jobs

Answer: E

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by Scott@TargetTestPrep » Mon Dec 02, 2019 6:01 pm
M7MBA wrote:In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs?

A. 27%
B. 21%
C. 19%
D. 18%
E. 16%

[spoiler]OA=E[/spoiler]

Source: Princeton Review
If the total number of people surveyed was 100, then there were 40 mothers and 60 fathers. Of these, 3/4 x 40 = 30 are employed mothers and 9/10 x 60 = 54 are employed fathers.

Thus, 100 - 84 = 16 or 16% of the 100 people surveyed are unemployed.

Answer: E

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