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When positive integer k is divided by 6 the remainder is 3.

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by BTGModeratorVI » Wed Mar 25, 2020 6:25 am

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B

C

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E

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Difficulty—

When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?

A) k + 1
B) k - 11
C) 4k + 2
D) (k - 3)/3 + 2
E) k/3

Answer: E
Source: Magoosh
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Re: When positive integer k is divided by 6 the remainder is 3.

by Brent@GMATPrepNow » Thu Mar 26, 2020 5:35 am
BTGModeratorVI wrote: ↑
Wed Mar 25, 2020 6:25 am
 When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?

A) k + 1
B) k - 11
C) 4k + 2
D) (k - 3)/3 + 2
E) k/3

Answer: E
Source: Magoosh
One approach is to TEST values.

When positive integer k is divided by 6 the remainder is 3
So, k could equal 3, 9, 15, 21, etc

let's TEST k = 3

a. 3 + 1 = 4 (EVEN)
b. 3 -11 = -8 (EVEN)
c. 4(3) + 2 = 14 (EVEN)
d. (3-3)/3 +2 = 2 (EVEN)

At this point, we can already see the answer must be E.
Let's check E for "fun"
e. 3/3 = 1 (ODD)
Great!
Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: When positive integer k is divided by 6 the remainder is 3.

by Scott@TargetTestPrep » Fri Mar 27, 2020 6:32 am
BTGModeratorVI wrote: ↑
Wed Mar 25, 2020 6:25 am
 When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?

A) k + 1
B) k - 11
C) 4k + 2
D) (k - 3)/3 + 2
E) k/3

Answer: E
Source: Magoosh
k can be values such as:

3, 9, 15, 21…

When we scan the answer choices, we see that all of these values are odd when they are divided by 3, so k/3 cannot be even.

Answer: E

Scott Woodbury-Stewart
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