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Que: An instructor gave the same test to three groups: P, Q, and R. The average (arithmetic mean) scores ...

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by Max@Math Revolution » Tue Dec 01, 2020 12:48 am

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Que: An instructor gave the same test to three groups: P, Q, and R. The average (arithmetic mean) scores for the three groups were 64, 84, and 72, respectively. The ratio of the numbers of candidates in P, Q, and R groups was 3: 5: 4, respectively. What was the average score for the three groups combined?

(A) 72
(B) 75
(C) 77
(D) 78
(E) 80
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Re: Que: An instructor gave the same test to three groups: P, Q, and R. The average (arithmetic mean) scores ...

by Max@Math Revolution » Wed Dec 02, 2020 11:51 pm
Solution: Let the number of candidates in groups P, Q, and R be 3k, 5k, and 4k, respectively, where ‘k’ is a constant of proportionality.

The average (arithmetic mean) scores for the three groups were 64, 84, and 72, respectively. The combined average for three groups is

=> \(\frac{\left[\left(64\cdot3k\right)\ +\ \left(84\cdot5k\right)\ +\ \left(72\cdot4k\right)\right]}{\left[\left(3k\ +\ 5k\ +\ 4k\right)\right]}\)

=> \(\frac{\left[192k\ +\ 420k+\ 288k\right]}{\left[12k\right]}\)

=> \(\frac{\left[900k\right]}{\left[12k\right]}\)= 75

Therefore, B is the correct answer.

Answer B
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