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If w1x1=y1z1, w2x2=y2z2, and w2<w1, is z1>z2? 1) x2&

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If w1x1=y1z1, w2x2=y2z2, and w2<w1, is z1>z2? 1) x2&

by Max@Math Revolution » Wed Feb 24, 2016 9:15 pm
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If w1x1=y1z1, w2x2=y2z2, and w2<w1, is z1>z2?

1) x2<x1
2) y1=y2


* A solution will be posted in two days.
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Source: — Data Sufficiency |
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by Max@Math Revolution » Sat Feb 27, 2016 7:21 pm
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If w1x1=y1z1,w2x2=y2z2, and w2<w1, is z1>z2?

1) x2<x1
2) y1=y2


In the original condition, there are 8 variables and 2 equations, which should match with the number of equations. So you need 6 equations. For 1) 1 equation, for 2) 1 equation, which is likely to make E the answer.
When 1) & 2), x2=y1=y2=w1=0, w2=-1. If x1=1, z1=2. If z2=1, it is yes. If z1=1, z2=12, it is no, which is not sufficient.
Therefore, the answer is E.
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