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Arithmetic

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Arithmetic

by BTGmoderatorRO » Fri Jan 05, 2018 6:23 am
Six distinct points lie in a plane such that 4 of the points are on line r and 3 of the points are on a different line,s.What is the total number of lines that can be drawn so that each line passes through exactly 2 of these 6 points?

a)3
b)4
c)5
d)6
e)8

OA is D
I cant get the true interpretation of this question, can an Expert help pls? Thanks in anticipation.
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by GMATWisdom » Fri Jan 05, 2018 9:51 am
Roland2rule wrote:Six distinct points lie in a plane such that 4 of the points are on line r and 3 of the points are on a different line,s.What is the total number of lines that can be drawn so that each line passes through exactly 2 of these 6 points?

a)3
b)4
c)5
d)6
e)8

OA is D
I cant get the true interpretation of this question, can an Expert help pls? Thanks in anticipation.
4Points are on line r and 3 on line s. But these two lines r and s are of no meaning to us as they pass through more than 2 points. As there are only six points on the said two lines the two lines must have a common point. Other than this common point there would be 2 points on line s and 3 points on the line r. These 3 points of r can be joined with 2 points of s in 3x2=6 ways making only 6 lines.
hence option D
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