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Source: — Data Sufficiency |
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by clar » Wed Aug 19, 2009 4:33 pm
the ans according to me should be A but it is given to be C

Can someone explain how?

my reasoning says that

if 3 is in P and x+3 is also in P , then all positive multiples of 3 will be in P.

this is because for both the above conditions to be valid , the value of x should be 0.

where am i faltering?
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by tohellandback » Wed Aug 19, 2009 6:44 pm
clar wrote:the ans according to me should be A but it is given to be C

Can someone explain how?

my reasoning says that

if 3 is in P and x+3 is also in P , then all positive multiples of 3 will be in P.

this is because for both the above conditions to be valid , the value of x should be 0.

where am i faltering?
you are right
A should be the answer.
because if 3 is there in the set then all the multiples must be there

a) SUFF

b)NOT SUFF, because it will depend upon what the set is
it can be {...-6,-3,0,3}
or it can be the infinite set {...-6,-3,0,3,6.....}
NOT SUFF
The powers of two are bloody impolite!!
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by acenikk » Thu Aug 20, 2009 6:25 am
I also go with A.
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by navalpike » Thu Aug 20, 2009 8:12 am
Could you please provide the source of the question so that we can avoid it?
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by PussInBoots » Thu Aug 20, 2009 11:43 am
Definitely A
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by iamjakekim » Thu Aug 20, 2009 4:58 pm
Why C?

I got E.

If X were 2, then we would get 5 or -1.
If X were 3, then we would get 6 or 3, hence multiple of 3.
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by woo » Fri Aug 21, 2009 4:37 am
C is right coz 0 is also a multiple of 3.
In fact, 0 is multiple of every natural number.
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