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Let function \(\#\) be defined as follows: \(\#(x)=\dfrac{x!+(x+1)!}{(x+2)!}.\) What is the value of \(\#(6)?\)

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by VJesus12 » Fri May 08, 2020 7:59 am

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Let function \(\#\) be defined as follows: \(\#(x)=\dfrac{x!+(x+1)!}{(x+2)!}.\) What is the value of \(\#(6)?\)

A. \(\dfrac{1}{10}\)

B. \(\dfrac{1}{9}\)

C. \(\dfrac{1}{8}\)

D. \(\dfrac{1}{7}\)

E. \(\dfrac{1}{6}\)

[spoiler]OA=D[/spoiler]

Source: Veritas Prep
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