Question from GPREP 4

Question stem : p and q are positive integers

Stmt I

p-q>n
p=100 q=90 n=1

p-q>n and p,q both greater than n

p=10 q=2 n=6

p-q>n but p,q both arenot greater than n

INSUFF

Stmt II

q>p

No info about n

INSUFF

Stmt I and II together

p-q>n
q>p

Add inequalities above facing the same direction

p-q+q>p+n
p>p+n

The only time this will happen is if n is negative since any positive number(p) cannot be greater than the same positive number p added to another positive number

Since p and q are gven to be positive we found n to be negative therefore p and q are both greater than n

C)

Quote

bacali: Master | Next Rank: 500 Posts; Posts: 245; Joined: Thu Aug 16, 2007 12:41 pm

by bacali » Mon Dec 22, 2008 8:57 am

Simpler way: If p-q>n and q>p then p-q must be negative. Since it's given that p and q are both positive therefore p-q is certainly smaller than both p and q.

Quote

cramya: Legendary Member; Posts: 2467; Joined: Thu Aug 28, 2008 6:14 pm; Thanked: 331 times; Followed by:11 members

by cramya » Mon Dec 22, 2008 8:50 pm

Simpler way: If p-q>n and q>p then p-q must be negative. Since it's given that p and q are both positive therefore p-q is certainly smaller than both p and q.

I dont understand what you are trying to say here. Please help me understand.

Quote

schumi_gmat: Master | Next Rank: 500 Posts; Posts: 377; Joined: Wed Sep 03, 2008 9:30 am; Thanked: 15 times; Followed by:2 members

by schumi_gmat » Mon Dec 22, 2008 10:14 pm

Cramya,

What he is trying to say is this -

from 1,
p-q>n

from 2, q>p i.e p-q<0

we know p and q are positive integers.
So again from 1, we have n<p-q i.e n< -ve

so both p and q are greater than n

Lets say from 2, q=10 and p =4
p-q=-6

From 1,
n<-6

Hence C