BTGmoderatorDC wrote:If y is odd, is z odd?
(1) xyz = odd
(2) yz = x
OA E
Source: Veritas Prep
Statements combined:
Case 1: y=1, z=1, x=1
yz=x --> 1*1 = 1
xyz = odd --> 1*1*1 = 1 = odd
In this case, z is odd, so the answer to the question stem is YES.
Case 2: y=3, z=1/3, x=1
yz=x -->(3)(1/3) = 1
xyz = odd --> (1)(3)(1/3) = 1 = odd
In this case, z is NOT odd, so the answer to the question stem is NO.
Since the answer is YES in Case 1 but NO in Case 2, the two statements combined are INSUFFICIENT.
The correct answer is
E.
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